PHYS 1202 / PHYS 1203 / PHYS 2311
Physics for the Life Sciences
Sample Answers, Question Sheet 6, 1999
Revision Questions - use these to guide your revision
- Conduction, convection and radiation are the three means by
which heat can be transferred. In what important way does radiation differ from the other
two?
- Stefan's Law for the power radiated by an object at temperature T is:
P
=
AeT4 .
Discuss the emissivity e, and explain what is meant by a black body.
What is the value of e for a perfect absorber? A perfect reflector?
- Explain the term basal metabolic rate, and use it to explain why a resting nude
person can become cold, even in a relatively warm room.
- Give examples of oscillating/vibrating systems, both mechanical and non-mechanical.
- Define the terms period, frequency and amplitude.
- What is meant by resonance?
Discussion Questions - for workshops and tutes
- Medical thermography (or thermology as it is sometimes called) is the clinical use of
the infra-red radiation emitted by the surface of the body. A good description of the
technique, with clinical examples, can be found at the Thermascan web site:
http://www.thermascan.com/home.htm
Keep in mind that this is a commercial web site, with a product to sell. We are purely
interested in the technique, not in evaluating the claimed clinical outcomes.
One of the claims made is that thermography "...is seen as an attractive means of
medical testing because it is absolutely safe, quick, simple for the patient..." Does
the claim of absolute safety seem reasonable? Contrast with a medical x ray.
Thermography is a passive process: it relies on detecting the
infra-red radiation emitted by the patient. (See Problem 2: a temperature difference of a
couple of degrees C changes the rate of energy emission by a couple of percent.) Because
of this, it is diff\icult to imagine how the process could be dangerous, except perhaps
that the patient might get cold! A medical x-ray, by contrast, involves firing x rays at
the patient. It is known that there is a small risk of contracting cancer from exposure to
x rays, but hopefully this risk is small compared to the potential benefits.
- A thin-walled stainless steel cup contains water at 89 oC. The outer
surface of the cup is highly polished, and there are two pieces of masking tape - one
white and one black - stuck to it. Explain why an infrared thermometer, preset to measure
the temperature of objects with emissivity of 0.95, records temperatures of 32 oC,
89 oC and 89 oC when pointed at the shiny steel,
the white tape and the black tape respectively. Can a black body be white?
The cup, the black tape, and the white tape all have
approximately the same temperature. Clearly, the thermometer does not work properly when
it is asked to measure the temperature of the shiny metal surface. The reason it that
while the tape - along with many other objects - has emissivity in the region of 0.95, the
shiny surface has a much lower emissivity. The rate of energy emitted by radiation depends
directly on the emissivity, thus the cup radiates less energy per unit time than a surface
at the same temperature, but with higher emissivity. In fact, the cup is radiating the
same amount of energy per unit area as an object with high emissivity (about 0.95) at a
temperature of 32 oC! Note that black body simply means
an object with emissivity 1: by this definition, the black and white tape qualify as
"black bodies".
- Under what circumstances can a thermometer in an incubator with a baby be a poor
indicator of the temperature of the baby? (Hint: A shiny thermometer can often have a very
low emissivity - making it a poor emitter of radiation as in the previous question - but a
baby's skin has e
1.)
A shiny thermometer may be a poor emitter/absorber of radiation
(viz the shiny cup in the previous question), so heat transfer will have to occur by
conduction and convection. The baby's skin, on the other hand, is an excellent
emitter/absorber of radiation. If the walls of the incubator are all at the same (room)
temperature, there will not be a big problem. The baby will exchange energy with the walls
by radiation, but this should not remove too much energy from the baby. The big problem
arises if one or more walls of the incubator are cold: this can happen if the incubator is
placed near a an uncovered, cold window. In this case, the incubator can cool due to
radiation to the cold window, and the baby can cool due to radiation to the cold
incubator. The thermometer, however, is not a good radiator and so may not cool in the
same way. Other means of recording the baby's body temperature are required: eg a rectal
or infrared thermometer.
Problems - these will be marked, and will count towards your final grade in
the topic
Due 5:00 PM on Monday 13th September.
- The sun has radius 6.96 x 108 m and surface temperature close to
6000 K. If its emissivity is e
1, how much energy does the sun radiate each second?
P = 4.47 x 1026 J/s
It's interesting to note that this power is about the same as would be radiated by
Avogadro's Number of 1 kW bar radiators!
- Two regions of skin have different temperatures: T1 = 33.0oC
and T2 = 31.6oC. Find the ratio of the rate at
which energy is radiated by 1 cm2 of skin in region 1 to the rate at which
energy is radiated by 1 cm2 of skin in region 2. That is, find P1/P2.
P1/P2 = 1.0185, ie P1
is about 2% greater than P2.
What does this suggest about the accuracy required if a thermograph is to distinguish
between the temperatures of these two regions?
The emitted radiation needs to be measured with accuracy better
than 2%.
- A copper pipe containing hot water has length 3 m, outer diameter 12 mm, and outer
surface temperature 80 oC. If the emissivity of the surface is e
= 0.95, and the surroundings are at 20 oC, at what net rate does the
pipe lose thermal energy due to radiation?
P = 49.7 W
- A pendulum consists of a mass at the end of a very thin rod. What is the length of the
rod if the period of the pendulum is 1.00 s?
L = 0.24824 m
- A clock uses a pendulum built from brass, which has a coefficient of linear expansion
= 19 x 10-6
(oC)-1. The clock keeps perfect time at 20 oC.
(a) At 0 oC, does the clock gain time or lose time? (b) How much time
does it gain or lose each hour?
(a) Pendulum is shorter, so period is shorter: Gains time.
(b) Gains approx 0.7 s each hour
This problem can be done without knowing the intitial length L0 of the
pendulum, by taking the ratio of the periods at the two different temperatures. Students
who are comfortable with a bit of algebra should try it this way. Otherwise, use the
length calculated in the previous question as the "20 oC"
length.
Leon Mitchell
1999-09-06